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Fix bad escaping in fzf-complete

Pierre Neidhardt
2017-05-25 19:29:42 +02:00
parent 2803c7e556
commit 6b6c9938aa
1 changed files with 11 additions and 9 deletions
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20
Examples-(fish).md

@@ -49,22 +49,24 @@ The following can replace fish completion menu with fzf. Because of a [fish bug]
function fzf-complete -d 'fzf completion and print selection back to commandline' function fzf-complete -d 'fzf completion and print selection back to commandline'
set -l complist (complete -C(commandline -c)) set -l complist (complete -C(commandline -c))
set -l result set -l result
string join -- \n $complist | sort | eval (__fzfcmd) -m --tiebreak=index --select-1 --exit-0 --header '(commandline)' | cut -f1 | while read -l r; set result $result $r; end string join -- \n $complist | sort | fzf -m --select-1 --exit-0 --header '(commandline)' | cut -f1 | while read -l r; set result $result $r; end
set prefix (string sub -s 1 -l 1 -- (commandline -t))
for i in (seq (count $result)) for i in (seq (count $result))
set -l r $result[$i] set -l r $result[$i]
## We need to escape the result. switch $prefix
switch (string sub -s 1 -l 1 -- (commandline -t))
case "'" case "'"
commandline -t -- (string escape -- (eval "printf '%s' '$r'")) commandline -t -- (string escape -- $r)
case '"' case '"'
set -l quoted (string escape -- (eval "printf '%s' '$r'")) if string match '*"*' -- $r >/dev/null
set -l len (string length $quoted) commandline -t -- (string escape -- $r)
commandline -t -- '"'(string sub -s 2 -l (math $len - 2) (string escape -- (eval "printf '%s' '$r'")))'"' else
commandline -t -- '"'$r'"'
end
case '~' case '~'
commandline -t -- (string sub -s 2 (string escape -n -- (eval "printf '%s' '$r'"))) commandline -t -- (string sub -s 2 (string escape -n -- $r))
case '*' case '*'
commandline -t -- (string escape -n -- (eval "printf '%s' '$r'")) commandline -t -- (string escape -n -- $r)
end end
[ $i -lt (count $result) ]; and commandline -i ' ' [ $i -lt (count $result) ]; and commandline -i ' '
end end